CHAPTER-10, OSCILLATIONS 1. The frequency of second’s pendulum is 1 Hz 2 Hz 5 Hz none of the above 2. A mass is suspended from a spring. The mass oscillates vertically. The total energy of the mass will be maximum at the highest location maximum at the mean position maximum at the lowest location same at all positions 3. The energy of the particle executing damped oscillations decreases with time, because work is done against elastic tension restoring force frictional force both restoring force and friction 4. A particle executes simple harmonic motion along a straight line path. Its amplitude is A. The potential energy of the particle is equal to the kinetic energy, when the displacement of the particle from the mean position is ±A / √2 ±A / 2 ±A Zero 5. The mass and diameter of a planet P are twice as compared to that of the earth. If the length of a second’s pendulum on the earth is lm, its length on the planet P will be 0.5 m l m 2 m 4 m 6. A hollow ball is filled with water and then used as a bob of the simple pendulum. If the water drains out of a small hole in the bottom, there. how will it affect the time period ? It will go on decreasing It will go on increasing It will first increase, and then it will decrease to ultimately acquire the initial value It will remain unchanged 7. The relation between the acceleration amplitude ‘ a’ , the displacement amplitude ‘A’ and the angular frequency co of SHM is A = ωa A = ω^{2}a a = ωA a = ω^{2}A 8. The length of second’s pendulum on the earth is about lm. What should be the length of second’s pendulum on the moon ? 1 m 1/6 m 6 m 36 m 9. A particle executes SHM. Its instantaneous acceleration is given by a = – px, where p is a constant and x is the displacement from the mean position. The angular frequency of the particle is given by √p p 1/√p 1/p 10. How does the total energy of an oscillator executing SHM vary ? Maximum at the mean position Maximum at the extreme position It is same every where Maximum at a point where potential energy is equal to the kinetic energy Loading … Question 1 of 10